(x^2+3x)^2-(x^2+3x)-6=0

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Solution for (x^2+3x)^2-(x^2+3x)-6=0 equation: 



(x^2+3x)^2-(x^2+3x)-6=0

We get rid of parentheses

-x^2+(x^2+3x)^2-3x-6=0

We add all the numbers together, and all the variables

-1x^2-3x+(x^2+3x)^2-6=0

We move all terms containing x to the left, all other terms to the right

-1x^2-3x+(x^2+3x)^2=6

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